test series

Question

On a TCP connection, current congestion window size is Congestion Window = 8 KB. The window size advertised by the receiver is Advertise Window = 10 KB. The last byte sent by the sender is LastByteSent = 18476 and the last byte acknowledged by the receiver is LastByteAcked = 12112. The current window size at the sender is _____________

Comments

what about unack bytes

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1828??

Answer 1

Sender's Window = min(Advertised Window , Congestion Window)

                          =min(8KB , 10KB )

                          = 8KB =8192B

Unacknowledged Bytes =18476B - 12112B = 6364B

Total Number of Bytes can sender sends = 8192 - 6364 = 1828 B

Comments

So current window size shud be 6364, right ?