Register

C Programming

218 views
–1 votes
–1 votes
Explaiin the working of printf() and scanf for different cases that could depict the complete picture of printf() and scanf()?
User Avatar

Please log in or register to answer this question.

Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

0 votes
0 votes
1 answer
1
Debargha Mitra Roy asked Apr 16
69 views
C Programming - Arrays & Pointer (NAT)
#include <stdio.h> int main() { int a[3][2] = {1, 3, 5, 7, 9, 11}; int *ptr = a[0]; ptr += sizeof(int); printf("%d", *ptr); return 0; } (Assume size of int to be $2$ bytes.) The output is __________.
#include <stdio.h int main() { int a[3] = {1, 3, 5, 7, 9, 11}; int *ptr = a[0]; ptr += sizeof(int); printf("%d", *ptr); return 0; }(Assume size of int to be $2$ bytes.)T...
User Avatar
0 votes
0 votes
2 answers
3
Debargha Mitra Roy asked Apr 10
116 views
C Programming - Recursion
What is the output of the below code? #include <stdio.h> void main() { static int var = 5; printf("%d ", var--); if (var) main(); } a. 1 2 3 4 5 b. 1 c. 5 4 3 2 1 d. Error
What is the output of the below code?#include <stdio.h void main() { static int var = 5; printf("%d ", var ); if (var) main(); }a. 1 2 3 4 5b. 1c. 5 4 3 2 1d. Error
User Avatar
1 votes
1 votes
1 answer
4
SSR17 asked Feb 29
254 views
c programming
#include <stdio.h> int main() { int i = -1; int x = (unsigned char)i; printf("%d", x); return 0; } output is 255 , but please explain how
#include <stdio.h int main() { int i = -1; int x = (unsigned char)i; printf("%d", x); return 0; }output is 255 , but please explain how
User Avatar
Link Copied!