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+6 votes
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How many disctict words can be formed by permuting the letters of the word ABRACADABRA?

  1. $\frac{11!}{5! \: 2! \: 2!}$
  2. $\frac{11!}{5! \: 4! }$
  3. $11! \: 5! \: 2! \: 2!\:$
  4. $11! \: 5! \: 4!$
  5. $11! $
asked in Combinatory by Veteran (87.2k points)  
retagged by | 138 views

3 Answers

+8 votes
Best answer

a) option answer .

answered by Veteran (20.8k points)  
selected by
+5 votes
The word 'ABRACADABRA' have 11 letters. Therefore total permutations is 11!

However they are not unique 11 letters and have duplicates repeated as follows.

A - 5 times

B- 2 times

R- 2 times

C and D are unique.

Therefore answer will be option A.
answered by Junior (581 points)  
0 votes

The correct answer is (A) 11! / (5!⨉2!⨉2!)

answered by Boss (5.3k points)  


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