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A fair coin is tossed until the same result turns up in succession(two head or two tail).Find the probability the number of tosses neede are even..

my approach ..P={P(x=2)+P(x=4)+P(x=6)+...}=0.33

Me answer 2*{P(x=2)+P(x=4)+P(x=6)+...}=0.66

what is the reason of this 2 multiplication?
asked in Probability by Veteran (18.3k points)   | 57 views

How to get success 

Either by HH , HTHH , HTHTHH , HTHTHTHH..........

OR 

TT , THTT , THTHTT , THTHTHTT 


I guess you took only 1 case.

got that! thanks

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