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asked in Mathematical Logic by Boss (8.7k points)  
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Given we have to form 4 mixed pairs for tournament i.e. we need 4 boys and 4 girls..

So we can select 4 boys from 5 in  C(5,4)  =  5 ways  

and also we can select 4 girls from 5 in 5 ways..

So by multiplication principle of counting , we have :

No of ways of making mixed pair team  =  5 * 5  =  25

Hence number of possible selections   =  25

answered by Veteran (68.7k points)  
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I too did same. but answer given is $600$
Don't worry ..It is the ACE test series..Endowed with mistakes..:)


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