GATE CSE
First time here? Checkout the FAQ!
x
0 votes
46 views

asked in Mathematical Logic by Boss (8.7k points)   | 46 views

1 Answer

+1 vote
Best answer

Given we have to form 4 mixed pairs for tournament i.e. we need 4 boys and 4 girls..

So we can select 4 boys from 5 in  C(5,4)  =  5 ways  

and also we can select 4 girls from 5 in 5 ways..

So by multiplication principle of counting , we have :

No of ways of making mixed pair team  =  5 * 5  =  25

Hence number of possible selections   =  25

answered by Veteran (66.5k points)  
selected by
I too did same. but answer given is $600$
Don't worry ..It is the ACE test series..Endowed with mistakes..:)


Top Users Jun 2017
  1. Bikram

    3704 Points

  2. Hemant Parihar

    1484 Points

  3. junaid ahmad

    1432 Points

  4. Arnab Bhadra

    1408 Points

  5. Niraj Singh 2

    1311 Points

  6. Rupendra Choudhary

    1194 Points

  7. rahul sharma 5

    1132 Points

  8. Debashish Deka

    1004 Points

  9. srestha

    932 Points

  10. Arjun

    930 Points

Monthly Topper: Rs. 500 gift card
Top Users 2017 Jun 19 - 25
  1. Bikram

    1960 Points

  2. Niraj Singh 2

    1306 Points

  3. junaid ahmad

    502 Points

  4. sudsho

    410 Points

  5. akankshadewangan24

    388 Points


23,355 questions
30,066 answers
67,371 comments
28,382 users