find the output

Question

Consider the following C program:
int fun(int p, int*q)
{
int n;
*q+=5;
n=*q;
p=p+n;
return(p+n);
}
main()
{
int i=0, *p, y;
p=&i;
y=fun(i, p);
printf("%d", y);
}
The output of the above program is ________.

1.   5
2.   10
3.   15

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here i is sent by value and address of i is sent in p

in func()--

first statment ,*q+=5 makes *q =5 which implies that i has become 5 now.so does p also become 5 here?i dun think so,because p is the copy of 'i'.it should not be changed to 5,it should stay 0 only.

now next statement p=p+n means p=0 +5=5

now,return statement (p+n) returns (5+5) =10

am i correct or not??

Comments

@Akriti yes 10 should be answer.

But how r u telling p=0? then return value also will be 5.

explain more.

---

*q+=5; (1)
n=*q;   (2)
p=p+n;  (3)
return(p+n); (4)

@srestha,till (2),p is 0 at (3) p becomes 5 because n is added to it.

den in return statement P+n returns 5+5 =10

thats what i am saying

Answer 1

Yes you are correct.

Formal paramaters are local data for the function. It gets erased after function scope is over. But any changes made by function to non-local (global data or any other data whose scope is not over yet accessed by function) data are retained.

In your question p can not become 5 because its a copy of local data

to function.

Comments

thanks for confirming