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Function f(x) = |cos x| is

(A) Continuous only in [0, π/2]
(B) Continuous only in [−π/2, π/2]
(C) Continuous only in [−π, π]
(D) None
asked in Set Theory & Algebra by Veteran (49.8k points)   | 63 views
answer is C?

continuous function 

@Pavan No, ans D)

@Debasish yes, then what?
it is continuous every where from graph we can say clearly
but it takes mod,

what is difference between cos x and |cos x| ?

see in the graph any where any certain point has two values no and any point function value is not defined no so the function is continuous this is a example of discontinuous https://en.wikipedia.org/wiki/Classification_of_discontinuities#/media/File:Discontinuity_jump.eps.png at x0 different values are there

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