3 votes 3 votes Databases ace-test-series databases er-diagram + – chaser asked Dec 30, 2016 • edited Mar 6, 2019 by akash.dinkar12 chaser 782 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply vishwa ratna commented Dec 30, 2016 reply Follow Share many to one. 0 votes 0 votes Surajit commented Dec 31, 2016 reply Follow Share many to one, ...chk this link below..1 st point. http://quiz.geeksforgeeks.org/minimization-er-diagram/ 1 votes 1 votes chaser commented Jan 2, 2017 reply Follow Share why can't it be one to one since in one to one as well..primary key of second table will b included in the first table and so A will functionally determine B 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes Many to one is correct answer. ankit3009 answered Sep 11, 2020 ankit3009 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes A-> B means Entity Set with A is Key constraints in relationship. So it has 1:1 cardinality with relationship and Entity Set with B has 1: M cardinality with relationship So the relationship is M:1 Arnab Bhadra answered May 24, 2017 • edited May 24, 2017 by Arnab Bhadra Arnab Bhadra comment Share Follow See all 4 Comments See all 4 4 Comments reply reena_kandari commented Jul 5, 2017 reply Follow Share Schema R represents a relationship, so I think the possible model will be many to many. 0 votes 0 votes joshi_nitish commented Jul 6, 2017 reply Follow Share you cant say A will be key, what if 'AC' is a key where C is not a candidate key.. 0 votes 0 votes joshi_nitish commented Jul 6, 2017 reply Follow Share it cant be many many when A->B and A and B are keys of some entities set... A B C 1 3 4 1 2 6 2 3 5..... above table is a case of many- many but it is not possible because it is voilating A->B..since now A(1) is not uniquely determing B... in the above relation only one-one or many-one(many on A side) is possible 0 votes 0 votes reena_kandari commented Jul 6, 2017 reply Follow Share yes,Many to one and one-to one is possible. IN this case C must be descriptive attribute.right? 0 votes 0 votes Please log in or register to add a comment.
