Let E,F, and G belongs to same universe of discourse U, then we can write E-F=E ∩ F' =EF' .
X = (E∩F) - (F∩G) = (E∩F) ∩ (F∩G)' =EF (F' + G') =EFG' =(E ∩F ∩G' )
Y=(E−(E∩G))−(E−F) =E (EG)' - (EF') = E(E'+G') - (EF') = EG' - EF'= EG' (EF')' = EG'(E'+F) =EFG' = (E∩F∩G')
We can clearly see that ,X=Y.
Option (C) X=Y is the correct answer.