Ans will be 12333
p=x Here p is holding the address of to 1st element of x.
Now, p is printing 1st element of x, i.e. 1
t=x+2;
Here t is holding address of x+$2\times size of int$=2000+$2\times4$=2008, i.e. addess of 3
q is a pointer that holding address of t.
So, q pointing same element as t
Now, p is preincremented, so it increment the address by 4 Bytes.
So, value pointed by p is 2
q and t already pointing to address of 3
So, output 12333