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Concept of layering.OSI and TCP/IP Protocol Stacks; Basics of packet, circuit and virtual circuit-switching; Data link layer: framing, error detection, Medium Access Control, Ethernet bridging; Routing protocols: shortest path, flooding, distance vector and link state routing; Fragmentation and IP addressing, IPv4, CIDR notation, Basics of IP support protocols (ARP, DHCP, ICMP), Network Address Translation (NAT); Transport layer: flow control and congestion control, UDP, TCP, sockets; Application layer protocols: DNS, SMTP, HTTP, FTP, Email.

.$$\scriptsize{\overset{{\large{\textbf{Mark Distribution in Previous GATE}}}}{\begin{array}{|c|c|c|c|c|c|c|c|}\hline
\textbf{Year}& \textbf{2022} & \textbf{2021-1}&\textbf{2021-2}&\textbf{2020}&\textbf{2019}&\textbf{2018}&\textbf{2017-1}&\textbf{2017-2}&\textbf{2016-1}&\textbf{2016-2}&\textbf{Minimum}&\textbf{Average}&\textbf{Maximum}
\\\hline\textbf{1 Mark Count} & 2 &1&1&2&1&3&2&3&2&3&1&2&3
\\\hline\textbf{2 Marks Count} & 4 &4&3&2&4&2&3&1&4&3&1&3&4
\\\hline\textbf{Total Marks} & 10 &9&7&6&9&7&8&5&10&9&\bf{5}&\bf{8}&\bf{10}\\\hline
\end{array}}}$$

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Recent questions in Computer Networks

2 votes
1 answer
2103
ISRO-DEC2017-34
Generally, TCP is reliable and UDP is not reliable. DNS which has to be reliable uses UDP because UDP is slower. DNS servers has to keep connections. DNS requests are generally very small and fit well within UDP segments. None of these.
Generally, TCP is reliable and UDP is not reliable. DNS which has to be reliable uses UDP becauseUDP is slower.DNS servers has to keep connections.DNS requests are genera...
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2 votes
2 answers
2106
ISRO-DEC2017-29
Using public key cryptography, $X$ adds a digital signature $\sigma$ to a message $M,$ encrypts $\langle M,\sigma \rangle$ and sends it to $Y,$ ... public key followed by ${Y}'s$ private key; Decryption:${Y}'s$ public key followed by ${X}'s$ private key.
Using public key cryptography, $X$ adds a digital signature $\sigma$ to a message $M,$ encrypts $\langle M,\sigma \rangle$ and sends it to $Y,$ where it is decrypted. Whi...
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2 votes
1 answer
2107
ISRO-DEC2017-30
Which of the following are used to generate a message digest by the network security protocols? (P) SHA-256 (Q) AES (R) DES (S) MD5 P and S only P and Q only R and S only P and R only
Which of the following are used to generate a message digest by the network security protocols? (P)SHA-256(Q)AES(R)DES(S)MD5P and S onlyP and Q only R and S onlyP and R o...
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3 votes
3 answers
2108
ISRO-DEC2017-31
In the IPv4 addressing format, the number of networks allowed under Class C addresses is $2^{20}$ $2^{24}$ $2^{14}$ $2^{21}$
In the IPv4 addressing format, the number of networks allowed under Class C addresses is$2^{20}$$2^{24}$$2^{14}$$2^{21}$
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1 votes
0 answers
2109
Tanenbaum Exercise problems
Suppose host A sends host B one segment with sequence number 38 and 4 bytes of data. Then in the same segment, the acknowledgment number is necessarily 42. True or False? please Explain Why?
Suppose host A sends host B one segment with sequence number 38 and 4 bytes of data. Then in the same segment, the acknowledgment number is necessarily 42. True or False?...
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0 votes
1 answer
2115
Digital signature doubt
Why do we need a "trusted third party" between a client and a receiver when sending a message with a digital signature? I mean what are the consequences if we don't do that?
Why do we need a "trusted third party" between a client and a receiver when sending a message with a digital signature?I mean what are the consequences if we don't do tha...
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0 votes
1 answer
2119
madeeasy work book
Tcp operates over a 40 Gbps link if TCP uses the full bandwidth continously how long in ms would it take the sequence number to wraparound completely?? answer is 0.859sec ??
Tcp operates over a 40 Gbps link if TCP uses the full bandwidth continously how long in ms would it take the sequence number to wraparound completely??answer is 0.859sec ...
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2 votes
1 answer
2120
TCP SEQUENCE NUMBER DOUBT
I have doubt 1: Segment sequence number is equal to the first sequence number of byte in TCP . Is it right ?
I have doubt1: Segment sequence number is equal to the first sequence number of byte in TCP . Is it right ?
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