Search results for limits

14 votes
7 answers
1
Compute $\displaystyle \lim_{x \rightarrow 3} \frac{x^4-81}{2x^2-5x-3}$$1$$53/12$$108/7$Limit does not exist
1 votes
2 answers
2
Evaluate the following limit:\[\lim _{x \rightarrow 0} \frac{\ln \left(\left(x^{2}+1\right) \cos x\right)}{x^{2}}= \]
26 votes
6 answers
4
$\displaystyle \lim_{x\rightarrow \infty } x^{ \tfrac{1}{x}}$ is$\infty $$0$$1$Not defined
25 votes
9 answers
6
$\displaystyle \lim_{x \to \infty}\frac{x-\sin x}{x+\cos x}$ equals$1$$-1$$\infty$$-\infty$
0 votes
1 answer
7
1 votes
1 answer
8
12 votes
4 answers
9
The value of the following limit is ________________.$$\lim_{x \rightarrow 0^{+}} \frac{\sqrt{x}}{1-e^{2\sqrt{x}}}$$
31 votes
8 answers
10
What is the value of $ \displaystyle\lim_{n \to \infty}\left(1 - \frac{1}{n}\right)^{2n}$ ?$0$$e^{-2}$$e^{-1/2}$$1$
0 votes
1 answer
11
How do we solve this question: $\lim n \to \infty \sqrt{n^2 + n} - {\sqrt{n^2 +1}}$
0 votes
1 answer
12
1.Evaluate the following definite integral $\int^{130}_{130}\frac{x^{3}-x\sin(x)+\cos(x)}{x^{^{2}}+1}dx$
0 votes
0 answers
13
Determine the volume of the solid obtained by rotating the portion of the region bounded by $y=\sqrt[3]{x}$ and $y=\frac{x}{4}$ that lies in the first quadrant about the ...
0 votes
0 answers
14
Depramine the area of region bounded by $y=2x^{2}+10$ and $y=4x+16$
0 votes
0 answers
15
Differentiate each of the following. $g(x)=\int ^{x}_{-4}e^{2t}cos^{2}(1-5t)dt$
0 votes
1 answer
16
Use the Squeeze Theorem to determine the value of $\lim_{x\rightarrow 0} x^{4}\sin (\frac{\pi}{x}).$$x^{4}\sin (\frac{\pi}{x}).$
0 votes
1 answer
17
Given that $7x\leq f\left ( x \right )\leq 3x^{2}+2$ for all determine the value of $\lim x\rightarrow 0 f(x)$
0 votes
0 answers
18
Determine all the number(s) c which satisfy the conclusion of Roles' Theorem for the given function and interval $f(x)=x^{2}-2x-8 $ on $ [-1,3]$
0 votes
0 answers
19
sketch the graph of $h(x)=-(x+4)^{3}$ and identify all the relative extrema and absolute extrema of the function.
3 votes
1 answer
20
Find the value of $\lim_{x \rightarrow 0 } \dfrac{x \tan2x - 2x\tan x}{(1-\cos 2x)^2} \rule{1 in}{.5 pt}.$