Search results for made-easy+databases

0 votes
1 answer
1
Isn’t F$^{+}$ minimal cover? If C $\rightarrow$ A is already there, then why does augmented CD $\rightarrow$ A needs to be?
0 votes
6 answers
3
Consider a relation $R(ABCDEFGH)$.How many superkeys will be there in relation $R$ if the candidate keys for relation are ${A, BC, CDE, EF}$?
1 votes
1 answer
6
Unique not null is equivalent to primary key.Relational Algebra and SQL has same expressive power.Which of the above statements are False?
0 votes
0 answers
8
0 votes
0 answers
10
0 votes
0 answers
11
Can someone please provide me with the correct explanation for this question
0 votes
1 answer
12
0 votes
2 answers
14
A relation is in 3NF if every non-prime attribute of R is fully functionally reliant on every key of RTRUEFALSE
1 votes
1 answer
15
Consider a relation schema r(A, B, C, D, E, F) and attribute A is element of every candidate key of r. Maximum number of possible candidate keys of r is ________.
1 votes
1 answer
16
0 votes
1 answer
17
0 votes
0 answers
18
0 votes
2 answers
19
1 votes
2 answers
20
The minimum number of tables needed to represent M,N,P,R1,R2 is …The given ans is 2.I think the ans should be 3.