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Recent questions tagged canonical-cover

0 votes
1 answer
1
Minimal Cover
In questions asking for the number of FDs in minimal cover if I get say A $\rightarrow$ B A $\rightarrow$ C D $\rightarrow$ EF Then what do I count them as 2 or 3 or 4 FDs?
In questions asking for the number of FDs in minimal cover if I get sayA $\rightarrow$ BA $\rightarrow$ CD $\rightarrow$ EFThen what do I count them as2 or 3 or 4 FDs?
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3 votes
1 answer
3
FD cover
F: { A-> BC, B->C, AC->B } G: { AB->C, A->B, A->C } Does G cover F?
F: { A- BC, B->C, AC->B }G: { AB->C, A->B, A->C }Does G cover F?
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3 votes
1 answer
4
Canonical cover
FDs are : A->C AC->D E->AD E->H Find : i) Number of FDs in canonical form. i) Number of FDs in minimal form.
FDs are :A->CAC->DE->ADE->HFind :i) Number of FDs in canonical form.i) Number of FDs in minimal form.
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1 votes
0 answers
5
canonical cover
for the relational scheme R=(A,B,C), and the set F of functional dependencies A BC B C A B AB C compute Fc .
for the relational scheme R=(A,B,C), and the set F of functional dependenciesA BCB CA BAB Ccompute Fc .
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0 votes
2 answers
8
Database:
Consider f is AB->C, C->A, BC->D, ACD->B, BE->C, CE->FA, CF->BD, D->E then find the canonical cover.
Consider f is AB->C, C->A, BC->D, ACD->B, BE->C, CE->FA, CF->BD, D->E then find the canonical cover.
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3 votes
1 answer
9
Made easy
Consider following set of FDs on R(A,B,C,D,E,F) A $\rightarrow$ BCD B $\rightarrow$ DE B $\rightarrow$ D D $\rightarrow$ A Compute the canonical cover.
Consider following set of FDs on R(A,B,C,D,E,F)A $\rightarrow$ BCDB $\rightarrow$ DEB $\rightarrow$ DD $\rightarrow$ ACompute the canonical cover.
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2 votes
4 answers
12
Canonical cover of a set
Consider the following set of functional dependency on the scheme (A, B,C) A-->BC, B-->C, A--> B, AB-->C The canonical cover for this set is: (A) A-->BC and B--> C B. A-->BC and AB--> C C. A--> BC and A--> B D. A--> B and B--> C
Consider the following set of functional dependency on the scheme (A, B,C) A >BC, B >C, A B, AB >C The canonical cover for this set is:(A) A >BC and B CB. A >BC and AB ...
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