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Recent questions tagged paging
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Paging
If Page size = Frame size is always true and offset in Logical address = offset in physical address holds Then how/why Logical address size can come different than physical address size?
If Page size = Frame size is always true and offset in Logical address = offset in physical address holdsThen how/why Logical address size can come different than physica...
Mrityudoot
103
views
Mrityudoot
asked
Mar 20
Operating System
paging
operating-system
memory-management
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–
0
votes
0
answers
2
memory management
we have 8 pages (each side 32B) to store in physical memory of 2^32 bits how many bits are required to identify each page , according to me 3 bits are required but that is wrong plz explain why
we have 8 pages (each side 32B) to store in physical memory of 2^32 bits how many bits are required to identify each page , according to me 3 bits are required but that i...
SSR17
186
views
SSR17
asked
Feb 8
Operating System
memory-management
operating-system
paging
virtual-memory
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–
9
votes
2
answers
3
GO Classes Test Series 2024 | Mock GATE | Test 14 | Question: 36
Assume a linear page table, with a 1-byte page-table entry. Assume physical and virtual address spaces of size 128 bytes with 32-byte pages. The page-table base register is set to physical address 16. The contents of ... What are the physical addresses that will get referred in fetch and execute of the above instruction? 10 42 102 70
Assume a linear page table, with a 1-byte page-table entry. Assume physical and virtual address spaces of size 128 bytes with 32-byte pages. The page-table base register ...
GO Classes
552
views
GO Classes
asked
Feb 5
Operating System
goclasses2024-mockgate-14
operating-system
memory-management
paging
multiple-selects
2-marks
+
–
5
votes
1
answer
4
GO Classes Test Series 2024 | Mock GATE | Test 13 | Question: 21
Consider a virtual memory system that uses paging. Virtual and physical addresses are both $32$ bits long, and the page size is $4 \textsf{KB}=2^{12}$ bytes. A process $\text{P}_1$ has the following page table. ... $\textsf{0x00003b65}$ $\textsf{0x00875b65}$ $\textsf{0x00875}$ Translation is not possible as per the given page table
Consider a virtual memory system that uses paging. Virtual and physical addresses are both $32$ bits long, and the page size is $4 \textsf{KB}=2^{12}$ bytes. A process $\...
GO Classes
352
views
GO Classes
asked
Jan 28
Operating System
goclasses2024-mockgate-13
goclasses
operating-system
paging
virtual-memory
1-mark
+
–
6
votes
2
answers
5
GO Classes Test Series 2024 | Mock GATE | Test 13 | Question: 45
Imagine a computer with a $32$-bit virtual address space and $\text{1 KB}$ pages. It uses a two-level page table system, with page-sized chunks at the inner level(not at the outer level). Suppose the code is located at address $0,$ and there are ... is $4$ Bytes.) $64 \mathrm{~KB}$ $2 \mathrm{~KB}$ $66 \mathrm{~KB}$ $16 \mathrm{MB}$
Imagine a computer with a $32$-bit virtual address space and $\text{1 KB}$ pages. It uses a two-level page table system, with page-sized chunks at the inner level(not at ...
GO Classes
705
views
GO Classes
asked
Jan 28
Operating System
goclasses2024-mockgate-13
goclasses
operating-system
paging
multilevel-paging
2-marks
+
–
4
votes
1
answer
6
GO Classes Test Series 2024 | Mock GATE | Test 12 | Question: 9
Consider a system with $4 \mathrm{~GB}$ of physical memory and $64 \mathrm{~GB}$ of Virtual Memory. The page size is $4 \mathrm{~KB}$. Recall that the page table is stored in physical memory and consists of PTEs (page ... each page could store $2048$ PTEs. How many pages does our page table occupy if we have a single-level page table?
Consider a system with $4 \mathrm{~GB}$ of physical memory and $64 \mathrm{~GB}$ of Virtual Memory. The page size is $4 \mathrm{~KB}$. Recall that the page table is store...
GO Classes
604
views
GO Classes
asked
Jan 21
Operating System
goclasses2024-mockgate-12
goclasses
numerical-answers
operating-system
virtual-memory
paging
1-mark
+
–
9
votes
1
answer
7
GO Classes Test Series 2024 | Mock GATE | Test 11 | Question: 20
Suppose that pages are $512 \mathrm{~B}$ and each page table entry is $4$ bytes. Assume that somehow the virtual and physical address spaces were both $4$ ... PTE we would look at? $\textsf{0x10000000}$ $\textsf{0x10000001}$ $\textsf{0x10000004}$ $\textsf{0x10000345}$
Suppose that pages are $512 \mathrm{~B}$ and each page table entry is $4$ bytes. Assume that somehow the virtual and physical address spaces were both $4$ GB and that the...
GO Classes
615
views
GO Classes
asked
Jan 13
Operating System
goclasses2024-mockgate-11
goclasses
operating-system
paging
1-mark
+
–
0
votes
0
answers
8
Made Easy Question : Multilevel Paging system, please refer the question below.
In this question, they have asked for memory requirements for page tables across the levels, solving which I am getting number of level 3 page tables as 2^8. Below is a brief of my approach, can anybody please explain if I am right or ... 3 PTs + level 4 PTs = 1 + 1 + 2^8 + 2^16 Where am I doing wrong? Please explain.
In this question, they have asked for memory requirements for page tables across the levels, solving which I am getting number of level 3 page tables as 2^8. Below is a b...
tishhaagrawal
229
views
tishhaagrawal
asked
Dec 5, 2023
CO and Architecture
paging
computer-architecture
gate-preparation
made-easy-test-series
multilevel-paging
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0
votes
1
answer
9
OPERATING SYSTEM
Assuming 3-level of paging is used by a paging system and a TLB for address translation. Calculate Average memory access time if each main memory access takes 100ns and TLB access time is 10ns, page fault service time is given as 200ns and TLB hit ratio is 80% and page fault rate is 10%.
Assuming 3-level of paging is used by a paging system and a TLB for address translation. Calculate Average memory access time if each main memory access takes 100ns and T...
24aaaa23
320
views
24aaaa23
asked
Oct 2, 2023
Operating System
operating-system
paging
effective-memory-access
+
–
0
votes
1
answer
10
Ace Test Series | Operating System | Paging
A machine supports a 48 bit virtual address and 32 bit physical address. Pages are 8KB. If the page table entry contains besides other information, one V/I bit, 1R, 1M and 2 bits for page protection. What is the page table size in bytes? 86 MB 128 MB 96 MB 512 MB
A machine supports a 48 bit virtual address and 32 bit physical address. Pages are 8KB. If the page table entry contains besides other information, one V/I bit, 1R, 1M an...
none30
286
views
none30
asked
Sep 4, 2023
Operating System
operating-system
ace-test-series
paging
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–
0
votes
1
answer
11
Can anyone explain , in the concept of segmentation . let the base address of a particular segment is 1900 and the limit of the segment is 400(i.e., size limit). Exactly what does it represent at the address 1900. Is it a page or group of pages or words
Unique_999
269
views
Unique_999
asked
Sep 3, 2023
Operating System
segmentation
operating-system
virtual-memory
paging
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–
0
votes
2
answers
12
Memory Management And Paging
Can Any explain the relationship between The “ Word Size “ and “ Logical Address Space “
Can Any explain the relationship between The “ Word Size “ and “ Logical Address Space “
Unique_999
293
views
Unique_999
asked
Aug 17, 2023
Operating System
operating-system
paging
memory-management
+
–
0
votes
1
answer
13
Paging , performance of paging w.r.t to space
Consider a System using Paging technique with an Address Space of65,536 Bytes. The Page Size in this System is 4096 Bytes. The Program Consists of Text, Data and Stack Sections as per the specifications given below: Text: 32,768 Bytes Data ... Address Space? b)What is the Maximum Page Size in Bytes such that the Program Fits in the Given Address Space?
Consider a System using Paging technique with an Address Space of65,536 Bytes. The Page Size in this System is 4096 Bytes. The Program Consists of Text, Data and Stack Se...
sumantsingh_
274
views
sumantsingh_
asked
Jun 4, 2023
Operating System
operating-system
paging
+
–
0
votes
1
answer
14
Andrew S. Tanenbaum (OS) Edition 4
A computer provides each process with 65536 bytes of address space divided into pages. A particular program has a text size of 32768 bytes, a data size of 16386 bytes, and a stack size of 15870 bytes. What is the maximum page size in bytes such ... the given address space? Each page must contain either text, data, or stack, not a mixture of two or three of them.
A computer provides each process with 65536 bytes of address space divided into pages. A particular program has a text size of 32768 bytes, a data size of 16386 bytes, an...
Syntax-error
402
views
Syntax-error
asked
Apr 24, 2023
Operating System
memory-management
paging
operating-system
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–
2
votes
2
answers
15
TLB with fault rate.
consider a paging system uses 1 level page table residing in RAM and TLB. RAM access time is 55 ns while TLB lookup takes 17 ns. Each page transfer takes upto 4700 ns to/from swap space. Miss ratio of TLB is 95% and Page fault ratio is 33%. Calculate the EMAT when TLB update time is negligible.
consider a paging system uses 1 level page table residing in RAM and TLB. RAM access time is 55 ns while TLB lookup takes 17 ns. Each page transfer takes upto 4700 ns to/...
shubhamsingh872
617
views
shubhamsingh872
asked
Apr 18, 2023
Operating System
operating-system
paging
+
–
0
votes
1
answer
16
#Memory Management #Paging #GATE
Consider a system which has LAS = PAS = ‘s’ bytes, page size is p bytes,Page table entry size is ‘e’ bytes Memory is byte addressable. Then what is the optimal value of page size by minimizing the memory overhead of maintaining the page table and internal fragmentation in paging?
Consider a system which has LAS = PAS = ‘s’ bytes, page size is p bytes,Page table entry size is ‘e’ bytes Memory is byte addressable. Then what is the optimal va...
Samridh28
448
views
Samridh28
asked
Apr 3, 2023
Operating System
paging
+
–
1
votes
1
answer
17
GO Classes 2023 | IIITH Mock Test 1 | Question: 29
Consider a system with $\mathrm{N}$ bytes of physical RAM, and $\mathrm{M}$ bytes of virtual address space per process. Pages and frames are $\text{K}$ bytes in size. Every page table entry is $\mathrm{P}$ bytes in size, accounting for the extra flags ... $\mathrm{M} / \mathrm{K} \ast \mathrm{P}$ $\mathrm{N} / \mathrm{P} \ast \mathrm{~K}$
Consider a system with $\mathrm{N}$ bytes of physical RAM, and $\mathrm{M}$ bytes of virtual address space per process. Pages and frames are $\text{K}$ bytes in size. Eve...
GO Classes
652
views
GO Classes
asked
Mar 26, 2023
Operating System
goclasses2023-iiith-mock-1
goclasses
operating-system
memory-management
paging
1-mark
+
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