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every vertex has a minimum degree, therefore, least number of edges that will be in the graph is given by the handshaking lemma as = min×|v|/2=2 E is right?

 

 

asked in Graph Theory by Active (2.5k points) 15 47 | 64 views

$\delta \leqslant \frac{2e}{v}\leq \Delta$.

Here $\delta$ is minimum degree and $\Delta$ is maximum degree.

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Minimum degree of an vertex is 0 so there is possibility of 0 edges.

If you are asking minimum number of edge in an connected graph then.

Least number of edges such that graph can be connected is simply n-1

Least number of edges to ensure that graph must be connected is $\frac{(n-1)(n-2)}{2}$+1 or n-1C2+1

Given equation in question seems to be ambiguous because there is no proper definition of min  what is min referred as?

answered by Boss (9.5k points) 5 29 58

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