2 votes 2 votes Using four cascaded counters with a total of 16 bits, how many states must be deleted to achieve a modulus of 50,000? A. 50,000 B. 65,536 C. 25,536 D. 15,536 Wanted asked Jan 5, 2017 Wanted 2.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes Here we have 4 cascaded counter of total of 16 bits..So it is equivalent to 16 bit ripple counter.. Hence ripple counter of 16 bit has modulus value = 216 = 65536 Hence to get modulus value of 50000 , no of states which must be deleted = Max no of state possible - 50000 = 15536 Hence D) is the correct answer Habibkhan answered Jan 5, 2017 Habibkhan comment Share Follow See all 2 Comments See all 2 2 Comments reply Wanted commented Jan 5, 2017 reply Follow Share 4 cascaded counter means 4 counter join serially ? 0 votes 0 votes Wanted commented Jan 5, 2017 reply Follow Share check thiz https://gateoverflow.in/100979/ace-self-dual I think answer is B 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes D)15536 Neeraj Chandrakar answered Jul 26, 2017 Neeraj Chandrakar comment Share Follow See all 0 reply Please log in or register to add a comment.