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24 votes
24 votes

How many $8-bi$t characters can be transmitted per second over a $9600$ baud serial communication link using asynchronous mode of transmission with one start bit, eight data bits, two stop bits and one parity bit?

  1. $600$
  2. $800$
  3. $876$
  4. $1200$
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3 Answers

Best answer
48 votes
48 votes

The baud rate is the rate at which information is transferred in a communication channel.
Serial ports use two-level (binary) signaling, so the data rate in bits per second is equal to the symbol rate in bauds.
Ref: https://en.wikipedia.org/wiki/Serial_port#Speed.

$\text{“9600 baud"}$ means that the serial port is capable of transferring a maximum of $\text{“9600 bits per second".}$

So, transmission rate here $=9600\text{ bps}$.

An eight bit data (which is a char) requires $1$ start bit, $2$ stop bits and $1$ parity bit $=12\text{ bits}$.

So, number of characters transmitted per second $=\dfrac{9600}{12}=800$.

Correct Answer: $B$

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1 votes
1 votes
Baud rate = 2* Bit rate

But this has no link to the question

So unlearn it.

as it is Asynchronous communication,

9600 is the baud rate

so 12 bits you have

No of characters transmitted per second= 9600/12 = 800
–3 votes
–3 votes
baud rate  = 2* bit rate

bit rate = 9600 / 2 = 4800 bps

# of 8-bit character that can be send  =  4800 / (1 + 8 + 2 + 1) = 400 chars

as there is no option matching I will go with 800 chars.

option B
Answer:

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