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0 votes

Given that a 22-inch monitor with an aspect ratio of 16:9 has a monitor resolution of 1920X1080,what is the width of the monitor ?

a)19.17 inches

b)22 inches

c)8.53 inches

d)10.79 inches

a)19.17 inches

b)22 inches

c)8.53 inches

d)10.79 inches

1 vote

0

First find diagonal in pixels

Square of dpx = square of 1920 + square of 1080 = 4852800

dpx = 2202.91 px (after calculating square root approx)

Now calculate pixels per inch ie. ppi

ppi = dpx / d = 2202.91 / 22 = 100.13 ( d is the diagonal in inches ie. 22 inches)

And now you can calculate its physical dimensions by dividing corresponding pixel dimensions by ppi:

Width = wpx / ppi = 1920 / 100.13 = 19.17 (wpx is the width in pixels ie 1920)

Or simply,

Sqrt (square of (19.17) + square of (10.79))

Pythagoras theorem right.

Square of dpx = square of 1920 + square of 1080 = 4852800

dpx = 2202.91 px (after calculating square root approx)

Now calculate pixels per inch ie. ppi

ppi = dpx / d = 2202.91 / 22 = 100.13 ( d is the diagonal in inches ie. 22 inches)

And now you can calculate its physical dimensions by dividing corresponding pixel dimensions by ppi:

Width = wpx / ppi = 1920 / 100.13 = 19.17 (wpx is the width in pixels ie 1920)

Or simply,

Sqrt (square of (19.17) + square of (10.79))

Pythagoras theorem right.

0

@bhoop1104 At last I think u did some mistake, correct me if I m wrong.

I think resolution is always vertical × horizontal.

U should divide like 1080/100.13 = 10.79

Option D