0 votes 0 votes An ordinary deck of 52 playing cards is randomly decoded into 4 piles of 13 cards each. The probability that each pile has exactly 1 ace is Anup patel asked Jan 8, 2017 Anup patel 1.2k views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply Sanjay Sharma commented Jan 8, 2017 reply Follow Share http://math.stackexchange.com/questions/529141/conditional-probability-sheldon-ross-example-2h 0 votes 0 votes muthu kumar commented Jan 19, 2019 reply Follow Share https://gateoverflow.in/102830/probability-numerical 0 votes 0 votes Please log in or register to add a comment.
2 votes 2 votes Just imagine that 4 aces are in different piles and then follow this approach: answer = $\frac{\binom{48}{12}*\binom{36}{12}*\binom{24}{12}*\binom{12}{12}*4!}{\binom{52}{13}*\binom{39}{13}*\binom{26}{13}*\binom{13}{13}}$ $\approx 0.105$ Sushant Gokhale answered Jan 10, 2017 Sushant Gokhale comment Share Follow See all 0 reply Please log in or register to add a comment.