Probability Numerical

Question

An ordinary deck of 52 playing cards is randomly decoded into 4 piles of 13 cards each. The probability that each pile has exactly 1 ace is

Comments

http://math.stackexchange.com/questions/529141/conditional-probability-sheldon-ross-example-2h

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https://gateoverflow.in/102830/probability-numerical

Answer 1

Just imagine that 4 aces are in different piles and then follow this approach:

answer

= $\frac{\binom{48}{12}*\binom{36}{12}*\binom{24}{12}*\binom{12}{12}*4!}{\binom{52}{13}*\binom{39}{13}*\binom{26}{13}*\binom{13}{13}}$

$\approx 0.105$