0 votes 0 votes Find the probability that a hand of five cards in poker contains four cards of one kind. Wanted asked Jan 9, 2017 Wanted 2.1k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Case 1: 4 Ace, 1 card can any out of remaining 48 Case 2: 4 cards of face '2', 1 card can any out of remaining 48 And so on for each 13 kinds. So, probablity = $\frac{\binom{48}{1}*13}{\binom{52}{5}}$ = $\frac{1}{4165}$ Sushant Gokhale answered Jan 10, 2017 Sushant Gokhale comment Share Follow See all 0 reply Please log in or register to add a comment.
