0 votes 0 votes The number of ways in which mn different object can be divided equally into m groups,each containing n objects,Please Explain Atul Verma12 asked Jan 10, 2017 Atul Verma12 463 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes I think this will work: $\frac{\binom{mn}{n}*\binom{mn-n}{n} *\binom{mn-2n}{n}*...}{m!}$ Try taking balls B1 B2 B3 B4 and distribute them into 2 groups/partitions with each group containing 2 balls. ---------------------------------------------------------------------- Simplified formula here Sushant Gokhale answered Jan 10, 2017 edited Jan 10, 2017 by Sushant Gokhale Sushant Gokhale comment Share Follow See all 3 Comments See all 3 3 Comments reply Rahul Jain25 commented Jan 10, 2017 reply Follow Share @sushant can you explain why divide by m. I understood to numerator part, but divide by m??? 0 votes 0 votes Sushant Gokhale commented Jan 10, 2017 reply Follow Share They arent like 'm' distinct groups. So, consider the balls example I gave above. Case 1: I choose B1, B2 firstly and B3, B4 in the last choose. Case 2: I chose B3, B4 firstly and then B1, B2 in the last case. So, I counted twice the same partitionning, right? Sorry, the denominator must be m! 0 votes 0 votes Rahul Jain25 commented Jan 10, 2017 reply Follow Share Yes now answer is corect. 1 votes 1 votes Please log in or register to add a comment.