1 votes 1 votes komal07 asked May 12, 2015 komal07 1.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes value of integral in (1,2) is zero. that means interval (1,x) and (x,2) having area with different sign.. atleast one crossing. atleast one real root.. Digvijay Pandey answered May 12, 2015 Digvijay Pandey comment Share Follow See all 3 Comments See all 3 3 Comments reply komal07 commented May 12, 2015 reply Follow Share Why it would have atleast 1 crossing ..?can you please explain in little more detail..? 0 votes 0 votes Digvijay Pandey commented May 12, 2015 reply Follow Share area under curve in (1,2) is 0.. that means der must be two (not exactly two it may be 1 or more than 2 alo) areas.. out of two, one is +ve and other is negative.. to get positive area graph should be above x axis and for negative area graph should below x axis.. and function is multiplication of trigonometric and polynomial that is everywhere continuous.. so der must be an crossing to get two area of different sign.. in case of only one area with zero value is nothing but root of a equation.. i.e. 1 crossing.. more than two area gives more than 1 crossing.. 0 votes 0 votes akshat sinha commented Dec 30, 2017 reply Follow Share number of crossings is number of real roots? 0 votes 0 votes Please log in or register to add a comment.
