Size of Disk Block =1024 Byte
Disk Blocks address = 32 bit, but 48 bit integers are used for address
Therefore address size = 6 bytes
No. of addresses per block 1024/6 = 170 addresses
Maximum File Size = 10 Direct + 1 Single Indirect + 1 Double Indirect + 1 Triple Indirect
= 10 + 170 + 1702 + 1703
≈ 222 Blocks
Since each block is of size 210 B
Maximum files size = 222 * 210 = 232 B
Answer - B