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+6 votes

A and B are the only two stations on an Ethernet. Each has a steady queue of frames to send. Both A and B attempt to transmit a frame, collide, and A wins the first backoff race. At the end of this successful transmission by A, both A and B attempt to transmit and collide. The probability that A wins the second backoff race is

  1. 0.5
  2. 0.625
  3. 0.75
  4. 1.0
asked in Computer Networks by Veteran (66.2k points) 1157 2200 2523 | 1.3k views

----->>>>i think it helps... 

3 Answers

+26 votes
Best answer

Find this solution. 

answered by (171 points) 3 4 6
selected by
nice explanation
So if a station wins the back-off, its K resets to 0?
k is the attempt number, if a packet is sent for the first time k=1, second time k=2 and so on.............
0 votes
ans b)
answered by Boss (5.3k points) 7 43 109
can you explain how did you calculate?
0 votes

watch the first 12 mins .. it's explained very well . 

answered by (403 points) 3 5

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