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Consider a multiplexer with $X$ and $Y$ as data inputs and $Z$ the as the control input. $Z=0$ selects input $X$, and $Z=1$ selects input $Y$. What are the connections required to realize the 2-variable Boolean function $f=T+R$, without using any additional hardware?

  1. $\text{R to X, 1 to Y, T to Z}$
  2. $\text{T to X, R to Y, T to Z}$
  3. $\text{T to X, R to Y, 0 to Z}$
  4. $\text{R to X, 0 to Y, T to Z}$
asked in Digital Logic by Veteran (59.7k points)
edited by | 974 views
0
Why not option c ?

1 Answer

+18 votes
Best answer

Answer is option A.

$Z'X + ZY$
Put  $Z = T, X = R, Y = 1 $ in $Z'X + ZY$
$= T'R + 1*T$

$= (T+T') (T+R)$
$= T + R$

answered by Veteran (55.6k points)
edited by
0
sir can u please make diagram(mux) for this question..
0

@Digvijay+Pandey

Should we consider f = T + R as SOP or POS ??

Answer:

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