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Determine the maximum length of cable (in km) for transmitting data at a rate of 5 mbps in a Ethernet LAN frames of size 1000 Bytes and propagation speed is 3 × 108 m/sec.

Your Answer:

240

Correct Answer: 48    Status: incorrect

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Given that ethernet frame :we apply

            TT = 2 *PT

          data size /  BW   = 2 *( length / velocity)

         ( 1000 *8 ) / ( 5 mbps)  =  2 * (  X / 3 * 108)

           X =  240000 = 240 KM

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