Given , DB size is 1 Bytes .
we need to find out number of bits in disk block address requires , let it be x bits = x/8 Bytes .
Given , max number of bytes of a file that can be accessed by quadruple pointer is 4 terabytes .
max number of bytes of a file that can be accessed by quadruple pointer = ( DBSize / DBA )4 * DBSize
= {1/ (x/8 ) }4 * 1
= ( 8/x)4
( 8/x)4 = 4 TB = 4 * 10004 byte
now find x from this equation ..