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can someone help me with example how A can be answer??

If we take A={1,2} and B= {1,2}

A U B={1,2} and A intersection B ={1,2}

then A U B is a subset of A intersection B condition is satisfied.

now if A=B then cardinality of A will be always equal to cardinality of B.

thus option a is incorrect as it is mentioned  "always".
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welcome..
@Arnabi You took an example and proved A is wrong which is perfect. But an example is not enough to prove B is correct though what you meant is correct.

@Arjun Sir can i say this as formal proof or should we take cases where A intersection B is phi

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