If only $1$ Node transmits, then in $1$ sec $\left \{ B = 1 Mb/s \right \}$ .
If all the 8 Nodes transmit, then in 1 sec $\left \{ B = 8 Mb/s \right \}$ .
Throughput of this shared network = Efficiency of the network * Bandwidth of the network = $0.75 * 10 Mb/s = 7.5 Mb/s$ .
At an average, Out of $10$ Mb/s, we receive throughput of only $7.5$ Mb/s .
When, all the $8$ Nodes are simultaneously transmitting, Bandwidth of only $8$ Mb/s can be reached, but at the end throughput can be only $7.5$ Mb/s $\left \{ Successful\ Transmission \right \}$.
Hence, Fraction which receives a collision = $\frac{8 - 7.5}{8} * 100 = 6.25 $% .