1 votes 1 votes Which grows faster when n increases? $I. n^{\frac{1}{3}}<\frac{n}{logn} II. n^{\frac{1}{3}}>\frac{n}{logn}$ Algorithms asymptotic-notation + – firki lama asked Jan 18, 2017 firki lama 400 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply santhoshdevulapally commented Jan 19, 2017 reply Follow Share Apply log on both side equations the it would be 1/3logn and logn-loglogn. // i consider log base is '2' n 1/3 logn logn-loglogn $2^{10}$ 3.33 7.2 $2^{64}$ 21.2 58 $2^{128}$ 42.2 121 $2^{256}$ 85.3 244 $2^{1024}$ 341.3 1021. .. .. .. 1 votes 1 votes firki lama commented Jan 19, 2017 reply Follow Share @santhoshdevpally so what the final conclusion....first statement true or second 0 votes 0 votes firki lama commented Jan 19, 2017 reply Follow Share by substitution method 99% more chances of getting wrong anser 0 votes 0 votes santhoshdevulapally commented Jan 19, 2017 reply Follow Share I is correct. 0 votes 0 votes Mahbub Alam commented Nov 19, 2018 reply Follow Share Option 1 is correct 0 votes 0 votes Please log in or register to add a comment.