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In a huge pile of apples and oranges, both ripe and unripe mixed together, $15$% are unripe fruits. Of the unripe fruits, $45$% are apples. Of the ripe ones, $66$% are oranges. If the pile contains a total of $5692000$ fruits, how many of them are apples?

1. $2029198$
2. $2467482$
3. $2789080$
4. $3577422$

Total fruits = $5692000$

$\qquad\qquad = \begin{Bmatrix} Unripe(15\%)\rightarrow 853800 \\ Ripe(85\%)\rightarrow 4838200\end{Bmatrix}$

$= \begin{Bmatrix} Unripe(15\%)\begin{Bmatrix}Apples(45\%)\rightarrow 384210\\Orange \rightarrow Don't\ care \end{Bmatrix} \\ Ripe(85\%)\begin{Bmatrix}Apples(34\%)\rightarrow 1644988\\Orange \rightarrow Don't\ care \end{Bmatrix} \end{Bmatrix}$

So, Total Apples = 384210 + 1644988 = 2029198

Correct Answer: $A$

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Let us consider pile contains 100%