2 votes 2 votes kirtikanwar asked Jan 20, 2017 kirtikanwar 1.1k views answer comment Share Follow See all 16 Comments See all 16 16 Comments reply Show 13 previous comments santhoshdevulapally commented Jan 22, 2017 reply Follow Share Even i have some doubt in this,now it is cleared. E1(n attributes) and E2(m entities) [n<=m]and E1-E2 participation on E1 side Then m acts like primary key. In the given diagram D is key. primary key may be simple or compound it is not allowed null values. 1 votes 1 votes Rahul Jain25 commented Jan 22, 2017 reply Follow Share Yeah. That should be the answer. Cheers to discussions and gateoverflow☺ 1 votes 1 votes santhoshdevulapally commented Jan 22, 2017 reply Follow Share Ha ha.... 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes 4 table i.E1{a,b,c} ii.E2{d,e,f} iii.E3{g,h} iv.R2{g,d} Abhishek prajapati answered Sep 5, 2017 Abhishek prajapati comment Share Follow See all 0 reply Please log in or register to add a comment.
–1 votes –1 votes in case of 1:1 relationship we can merge the two tables into a single table but here where is 1:1 ..is it b/w E2 and E3?? ?? cse23 answered Jan 22, 2017 cse23 comment Share Follow See all 0 reply Please log in or register to add a comment.