Perimeter(window) $= 6$ m

$\implies 5a = 6$ m

$\implies a = \dfrac{6}{5}$ m

$\implies a = 1.2$ m

Area(window) $=$ Area(triangle) $+$ Area(square)

$\qquad = \dfrac{\sqrt{3}}{4}a^2 + a^2$

$\qquad = \dfrac{\sqrt{3}}{4}{(1.2)}^2 + {(1.2)}^2$

$\qquad = 2.06 \ \text{m}^2$

Correct Answer: $B$