0 votes 0 votes Compiler Compiler Design compiler-design parsing first-and-follow + – Deepak Yadav asked Jan 25, 2017 retagged Jun 18, 2022 by Lakshman Bhaiya Deepak Yadav 538 views answer comment Share Follow See all 7 Comments See all 7 7 Comments reply Show 4 previous comments sudsho commented Jan 23, 2017 reply Follow Share kunal first of A is first of B right..means epsilon so in this case u have to check whether A is nullable or not...so if u substitute epsilon in place of B u'll get first of A as c.... 2 votes 2 votes bad_engineer commented Jan 23, 2017 reply Follow Share why option A is not correct means First(A) = {epsilon,c}??? 0 votes 0 votes sudsho commented Jan 23, 2017 reply Follow Share ^first of A is epsilon means BCD is epsilon..is it possible here? 2 votes 2 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes First(A) = c Follow(D) = $ targate2018 answered Jan 25, 2017 selected Jan 25, 2017 by focus _GATE targate2018 comment Share Follow See all 0 reply Please log in or register to add a comment.
2 votes 2 votes First(A) = c Follow(D) = Follow(A) = $ targate2018 answered Jan 25, 2017 targate2018 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes option d is right. abhishekmehta4u answered Mar 11, 2019 edited Mar 11, 2019 by abhishekmehta4u abhishekmehta4u comment Share Follow See all 0 reply Please log in or register to add a comment.