Statement 1:
6000 rpm
6000 round in 60second
1 round= 60/6000=10ms
in 10 ms
so average latency=10/2=5ms satisfying
statement 2
in one entire rotation, a track is read
track=sector*sector size=128KB
so 128KB is read on 10ms
10ms->128KB
1000ms=1s->128*100=12800KB=12.8MB
1 so stament 2 satisfying
Statement 3:
Track capacity=128 sector*sector size=128KB ...Not satisfying
so C is correct answer