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An apple vendor sells half the number of existing apples plus $1$ to the first customer, sells $1/3$$^{rd}$of the remaining apples plus $1$ to the second customer and $1/5$$^{th}$  of the remaining apples plus $1$ to the third customer. He then finds that he has $7$ apples left. If each apple costs $Rs.12$, then the amount of  money he collected while selling apples is _______
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Here everything is very easy just you need to take care of your calculation part . Think smartly you will get the solution easily .

Lets take apples are X .

given to 1st costumer half + 1 so how much is left = X/2 -1

from remaining, 1/3rd of remaining + 1 to second costumer , so how much left (2/3rd -1) = 2/3 [X/2 -1] -1
from remaining 1/5th of remaining +1 to 3rd customer , so how much left = 4/5[2/3[X/2 -1] -1] -1

it is given 7 so equate both
4/5[2/3[X/2 -1] -1] -1  =7

after solving you will get X=35 , as at the last 7 apples were left so sold apples are = 28
so total cost = 28*12 (12 is the cost of one apple ) = 336

but as i did reverse enginnering i found data is not appropriate , as total apples are 35 so first customer got half +1 = 35/2+ 1= 17.5+1 =18.5 , but it should be integer . 

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