0 votes 0 votes focus _GATE asked Jun 5, 2015 focus _GATE 533 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes no of lines in the cache=> cache size/Block size=> 217/26=>211 no of sets=no of lines/X => X= associativity 29=211/X=> X=22=>4 way set associative Joker answered Mar 6, 2016 • selected Mar 6, 2016 by abhilashpanicker29 Joker comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes 512 Set 64B block size. No of sets = 128kB/512*64 = 4 Digvijay Pandey answered Jun 5, 2015 Digvijay Pandey comment Share Follow See all 0 reply Please log in or register to add a comment.
