MadeEasy CBT 2 q32

Question

Correct Resilt

Comments

Tclk >= 2 * 2 ns + 1 ns

Tclk >= 5 ns  or 200MHZ      option B is right :)

Answer 1

A) delay due to FF0 is 2ns and the Q0 is clock for FF1 hence clock is divided by 2(because a FF act as frequency divider ) hence  2ns*2=4ns and due to AND gate 1ns and FF2 has 2ns 

hence  total delay 2+4+1+2 ns=7ns

frequency =1000/7 =143MHz