L1 is not context free language, L2 is context free language
L1={ ${ a^{n}b^{n},∣ n≥0,n≠100}$}
here variable n has two comparisons n≠100 and equal number of a and b so not context free
L2={${w∈{(a,b,c)}^{∗}∣ na(w)=nb(w)=nc(w)}$}
it is not context free number of comparisons more than 1 ,equal number of a,b,c{a=b and b=c }