1 votes 1 votes How many minimum bits are required to represent $-16$ in $2's$ complement form Digital Logic digital-logic number-representation virtual-gate-test-series + – cse23 asked Jan 31, 2017 • edited Apr 2, 2019 by Lakshman Bhaiya cse23 431 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply Lokesh . commented Jan 31, 2017 reply Follow Share 2's complement range $-2^{n-1} \ to\ 2^{n-1}-1$ so for -16 it needs 5 bits 0 votes 0 votes bad_engineer commented Jan 31, 2017 reply Follow Share 10000 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes We know the range of 2's complement is from -2n-1 to 2n-1-1 now -16=-2n-1 n-1=4 n=5 5 bits required Aboveallplayer answered Jan 31, 2017 Aboveallplayer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes -16 in 2's Complement is 100000 hence 5 bits Neeraj Chandrakar answered Jul 25, 2017 Neeraj Chandrakar comment Share Follow See all 0 reply Please log in or register to add a comment.