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Newton-Raphson method is used to compute a root of the equation $x^2 - 13 = 0$ with 3.5 as the initial value. The approximation after one iteration is

1. 3.575
2. 3.676
3. 3.667
4. 3.607
closed with the note: out of syllabus
closed | 572 views
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x=3.5 - ((3.5^2)-13)/(2*3.5) so x=3.607 it is from the next term formula of newton raphson method
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What is the formula, Sir?
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I have seen this formula, but it looks like  Bhagirathi  is using some other formula

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same formula is used, x1= x0-f(x0)/f'(x0)

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+1 vote