Arrays

Question

How to solve this question ?

Answer 1

store the array in row major

1	2	3	4	5	6	7	8	9	10	11	12
0010	0210	0410	0610	0810	1010	1210	1410	1610	1810	2010	2210

now convert to 2d

arr[0]

100	202
304	406
508	610

arr[1]

712	814
916	1014
1116	1218

arr= arr+0 = 00 and arr[1]=arr+1=12  as (arr+1) gives the address of next 2D array in that 3D array. So arr[1]-arr[0] = (12₁₀-00₁₀)/ 2 =12/2 = 6 ( where 2 is the size of integer data type ).

Again , arr[1][0] =*(arr+1)+0 = 12 , i.e points to first row of second 2D array of this 3D array. arr[0][0]= *(arr+0)+0 = 1000_10.So arr[1][0]- arr [0][0] = (12₁₀-00₁₀)/ 2 =12/2 = 6

Comments

Why are you dividing by 2?
I am not getting

Answer 2

After running the code 

 

ANS is 3 6 which u can see in given image

(NOTE : X represents base value)

for given 3d array  have a 2*3 element in each layer

means each plane have total 6 element which means for a[1] have value  X+6*2=X+12

and for a[0]=X+0*2=X;

similar for a[1][0] and a[0][0]

a[1]-a[0] = (X+12-X)/4(size of row which have 2 element) = 3

a[1][0]-a[0][0] = (X+12-X)/2(size of each element) =  6

Comments

"a[1]-a[0] = (X+12-X)/4(size of row which have 2 element) = 3"

Why are you diving my size of row with 2 elements?

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i divided by 4 because one element of 3d array is one row not one element

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shouldn't one element of 3-d array be a 2-d array?