The Gateway to Computer Science Excellence
First time here? Checkout the FAQ!
x
+13 votes
1.4k views

What is the possible number of reflexive relations on a set of 5 elements?

  1. $2^{10}$
  2. $2^{15}$
  3. $2^{20}$
  4. $2^{25}$
asked in Set Theory & Algebra by Boss (18k points)
edited by | 1.4k views
0

This might help ...

2 Answers

+25 votes
Best answer

A relation consists of set of ordered pairs $(a,b)$. Here $a$ can be chosen in $n$ ways and similarly $b$ can be chosen in $n$ ways. So, totally $n^2$ possible ordered pairs are possible for a relation. Now each of these ordered pair can either be present in the relation or not- 2 possibilities for each of the $n^2$ pair. So, total number of possible relations =  $$2^{\left(n^2\right)}$$.

Now, for a relation $R$ to be reflexive, ordered pairs $\left\{(a,a) \mid a \in S \right\}$, must be present in $R$. i.e.; the relation set $R$ must have $n$ ordered pairs fixed. So, number of ordered pairs possible is $ n^2 - n$ and hence total number of reflexive relations is equal to $$ 2^{\left(n^2-n\right)}$$.

for $n=5$, answer will be, $2^{5^2-5}=2^{20}$

therefore $option\ C$ is correct

answered by Veteran (342k points)
edited by
+6 votes
The number of reflexive relations =2^(n^2 - n) so option c is correct
answered by Boss (14.1k points)


Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true

35,499 questions
42,765 answers
121,498 comments
42,150 users