0 votes 0 votes iita asked Feb 3, 2017 iita 1.2k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes 4K 8K 20K 2K 2K memory slot=job j1 (0-4) time 20k memory slot=job j2(0-10) time,j6(10-11) time. 8K memory slot=job j4(0-4) time,j5(4-8) time,j7(8-16). 4K memory slot=job j3(0-2) time. so completion of job j7 will be 16 time unit. BASANT KUMAR answered Aug 21, 2018 BASANT KUMAR comment Share Follow See all 0 reply Please log in or register to add a comment.