$F(x, y, t) \implies$ person $x$ can fool person $y$ at time $t.$
For the sake of simplicity propagate negation sign outward by applying De Morgan's law.
$∀x∃y∃t(¬F(x,y,t)) \equiv ¬∃x∀y∀t(F(x, y, t))$ [By applying De Morgan's law.]
Now converting $¬∃x∀y∀t(F(x, y, t))$ to English is simple.
$¬∃$$x$$∀$$y$$∀$$t(F(x, y, t))$ $\implies$ There does not exist a person who can fool everyone all the time.
Which means No one can fool everyone all the time.
So, option (B) is correct.