$F(x, y, t) \implies$ person $x$ can fool person $y$ at time $t.$
For the sake of simplicity propagate negation sign outward by applying De Morgan's law.
$∀x∃y∃t(¬F(x,y,t)) \equiv ¬∃x∀y∀t(F(x, y, t))$ [By applying De Morgan's law.]
Now converting $¬∃x∀y∀t(F(x, y, t))$ to English is simple.
$\color{blue}{¬∃}x\color{green}{∀}y\color{red}{∀}t(F(x, y, t))\implies \color{blue}{\text{ There does not exist }}$$ \text{a person who can fool }$$\color{green}{\text{everyone}} $$\color{red}{\text{ all}} \text{ the time.}$
Which means No one can fool everyone all the time.
So, option (B) is correct.