0 votes 0 votes Digital Logic digital-logic combinational-circuit + – mohit chawla asked Feb 4, 2017 mohit chawla 391 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply Akriti sood commented Feb 5, 2017 reply Follow Share i am getting sigma(4,5,6,7) actually,select lines are A and A', (A)'.(A')'.A + (A)'.A'.0 + A,(A')'.1 + A.A'.A' = A which can b written as ABC + AB'C' + AB'C + ABC' 0 votes 0 votes mohit chawla commented Feb 5, 2017 reply Follow Share answer is given as c. @akriti 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes There is an little dot at enable In many of made easy test is equivalent to not gate So enable=0 all entries in k map is zero Hence in pos form it will be $\prod$M(0,1,2,3,4,5,6,7) Hence option C Tesla! answered Mar 30, 2017 • edited Jul 14, 2017 by Tesla! Tesla! comment Share Follow See all 2 Comments See all 2 2 Comments reply vishal gupta 2 commented Jul 14, 2017 reply Follow Share enable input is zero .all the entries in kmap will be zero. C seems correct. 0 votes 0 votes Tesla! commented Jul 14, 2017 reply Follow Share Thanks for correction 0 votes 0 votes Please log in or register to add a comment.