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Q1. Three indian and three chinese split into subgroups having atleast one indian. How many subgroups are possible?

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1 indian && (0 or 1 or 2 or 3) chinese = 3C1 × [3C0 + 3C1 + 3C2 + 3C3] = 3 × [8]

2 indian && (0 or 1 or 2 or 3) chinese = 3C2 × [3C0 + 3C1 + 3C2 + 3C3] = 3 × [8]

3 indian && (0 or 1 or 2 or 3) chinese = 3C3 × [3C0 + 3C1 + 3C2 + 3C3] = 1 × [8]

Total sets = 8× (3+3+1) = 56

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